geometry
posted by DEE
in triangle ABC, PandQ are points on BC such that BQ=CP and AP=AQ.show thatAB=AC

Arora
In this case, APQ forms an isoceles triangle, which you'll see if you draw a figure. (AP=AQ)
So, ∠APQ = ∠AQP
=> 180  ∠APQ = 180  ∠AQP
=> ∠AQB = ∠APC .....1
Now, consider triangles AQB and APC
AP = AQ (Given in the question)
∠AQB = ∠APC (From ...1)
QB = PC (Given in the question)
Hence, the two triangles AQB and APC are congruent by the SAS rule.
Since the corresponding parts of congruent triangles are equal, AB=AC
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