Derivatives
posted by Ismail
Determine the interval on which The function is differentiable :
f(x) = 3x  5

Ismail
I know that if f is differntiable on (a,infinity) and the one side limt f(x) f(a) / xa exists then its differntiable on [a,infinity)
I found the interval of the function which appears to be (infinty,infinity)
i.e R .. all real numbers
But i really cant find the interval of the derivtive !!! 
Damon
You answered the question you asked, the function is differentiable for all real values of x
The derivative is the slope of that straight line, 3 , so 3 and only 3
Respond to this Question
Similar Questions

mean value theorem
Show that the function f(x)=1x, [1,1] does not satisfy the hypotheses of the mean value theorem on the given interval. Also how do I graph the function together with the line through the points A(a,f(a)) and B(b,f(b)). Also how … 
unique solution
How do I show that the equation x^4 + 3x + 1 = 0, 2 <= x <= 1 has exactly one solution in the interval. Thanks. One way to do this is to use trial and error. split the interval (2,1) into 10 equal parts. Then evaluate the … 
calc again!
i got answers for this one, but i feel like i did something wrong. f(x)= 2x+1 when x is less than or equal to 2 (1/2)x^2 + k when x is greater than 2 1) what value of k will make f continuous at x = 2? 
Calculus
Show that the function f(x)= x^(3) +3/(x^2) +2 has exactly one zero on the interval (infinity, 0). So far this is what I have: 0=x^3 + 3/(x^2) +2 2= (1/x^2)(x^5 + 3) 2x^2= x^5 +3 But now I'm stuck. I also am not sure if this is … 
Calculus
Determine whether Rolle's Theorem can be applied to f on the closed interval [a,b]. If Rolle's Theorem can be applied, find all values of c in the open interval (a,b) such that f'(x)=0. f(x) = x^(2/3)  1 [8,8] I plugged in both values … 
Math11
Hello, I don't know how to do this, please help. Thank you. 1).Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? 
Math (Function differentiable)
Determine whether the function is differentiable at x=2 x^2+1 for x<(or equal to) 2 4x3 for x>2 I did the math for the limits of both equations and they both approach to 4. So that means they are differentiable right? 
calculus
Rolle's theorem cannot be applied to the function f(x) = x1/3 on the interval [–1, 1] because Answer Choices: f is not differentiable on the interval [–1, 1] f(–1) ≠ f(1) f is not differentiable on the interval [–1, 1] and … 
calculus
Rolle's theorem cannot be applied to the function f(x) = x^1/3 on the interval [–1, 1] because... f is not differentiable on the interval [–1, 1] f(–1) ≠ f(1) f is not differentiable on the interval [–1, 1] and f(–1) ≠ … 
Calculus Please Check my answers
f is a function that is differentiable for all reals. The value of f ′(x) is given for several values of x in the table below. The table: x 8,3,0,3,8 f'(x)4,2,0,4,5 If f ′(x) is always increasing, which statement about f(x) …