Physics
posted by Ismail .
A and B are vectors in the same plane. If A= 8i+6j. Find the vector B such that A+B = 14.14 units and A is perpendicular to B.

A is perpendicular to B
so
A dot B = 0
AxBx + AyBy = 0
8 Bx + 6 By = 0
and
A + B = (Ax + Bx)i+ (Ay+By)j
A+B^2 = 14.14^2 = (Ax+Bx)^2+(Ay+By)^2
so
(Ax+Bx)^2+(Ay+By)^2 = 100
(8+Bx)^2 +(6+By)^2 = 100
but we know
By =(8/6)Bx = (4/3) Bx
plug and chug. 
Sorru for the inconvenience... but I didnt get this concept
A+B^2 = 14 ??!! 
A+B^2 = 14.14^2 = 200 not 100
I did not use calculator, knew sqrt 2 = 1.414 
Oh .. the rest of the steps are the same then ?

yes
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