Calculus
posted by Mike .
Find y that satisfies the given condition
dy/dx=20x(5x^21)^3; curve passes through (1,3)
I took the antiderivative and ended up with 10x^2((5x^21)^4/4). I end up with a large number at the end, which I think might be wrong.

Calculus 
Steve
let
u = 5x^21
du = 10x dx
so, what you have is 2u^3 du
y(x) = u^4/2 = 1/2 (5x^21)^4 + C
y(1) = 3, so
1/2 (51)^4+C = 3
2C = 6256 = 250
y(x) = 1/2 (5x^21)^4  125
Had you checked your function, you would have seen that its derivative was not the original dy/dx.
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