Two mechanics worked on a car. The first mechanic worked for
10
hours, and the second mechanic worked for
5
hours. Together they charged a total of
$1525
. What was the rate charged per hour by each mechanic if the sum of the two rates was
$200
per hour?
f = 1st mech , s = 2nd mech
10 f + 5 s = 1525
f + s = 200
solve the system using substitution or elimination
Two mechanics worked on a car. The first worked for 5 hours and the second worked for 15 hours. Together they charge a total of $1825. What was the rate charge per each mechanic if the sum of the two rates was $165 per hour
Two mechanics worked on a car. The first mechanic worked for hours, and the second mechanic worked for hours. Together they charged a total of . What was the rate charged per hour by each mechanic if the sum of the two rates was per hour?
Note that the ALEKS graphing calculator can be used to make computations easier.
To solve this problem, we can set up a system of equations.
Let's assume the first mechanic charges $x per hour, and the second mechanic charges $(200-x) per hour.
We know that the first mechanic worked for 10 hours, so the total amount charged by the first mechanic is 10x.
Similarly, the second mechanic worked for 5 hours, so the total amount charged by the second mechanic is 5(200-x).
Together, the total amount charged by both mechanics is $1525.
So, we can write the equation:
10x + 5(200-x) = 1525
Now, let's solve this equation to find the value of x.
10x + 1000 - 5x = 1525
5x = 525
x = 525/5
x = 105
Therefore, the first mechanic charged $105 per hour, and the second mechanic charged $(200-105) = $95 per hour.