I am a 2-digit number. My ones is 3 more than my tens and the sum of my digits is 11. What number am I ?
5 + 6 = 11
4 + 7 = 11
3 + 8 = 11
2 + 9 = 11
Which of those meets the other criteria?
3+8=11
Nope. There's only supposed to be a difference of 3.
8 - 3 = 5
so, what number am i?
Haven't you learned to subtract single digit numbers yet?
ok i got it,,thanks
To find the number, let's break down the given information.
1. "My ones is 3 more than my tens": This means that the digit in the ones place is greater than the digit in the tens place by 3.
2. "The sum of my digits is 11": This indicates that the sum of the digits in the number is equal to 11.
Now, let's solve it step by step:
Step 1: In a two-digit number, let the digit in the tens place be represented by 'x' (any number from 0 to 9).
Step 2: According to the first condition, the digit in the ones place is 3 more than the digit in the tens place. So, the digit in the ones place can be represented by 'x + 3'.
Step 3: Now, we know that the sum of the digits is 11. So, we can write the equation: x + (x + 3) = 11. Simplifying this equation gives us: 2x + 3 = 11.
Step 4: To solve for 'x', we subtract 3 from both sides of the equation: 2x = 11 - 3, which gives us 2x = 8.
Step 5: Finally, we divide both sides of the equation by 2 to solve for 'x': x = 4.
So, the digit in the tens place is 4, and the digit in the ones place is 4 + 3 = 7.
Therefore, the number is 47.