So;Arrange the following species in order of decre asing S-O bond strength (strongest first, weakest
last). SO, SO 3
2– , SO 3 , SO 2
I got SO2, sO32-, SO3, SO. Any ideas
To arrange the given species in order of decreasing S-O bond strength, we need to compare the bond strengths between sulfur (S) and oxygen (O) for each species.
The general trend for S-O bond strength is that it increases with increasing oxidation state of sulfur. This means that species with higher oxidation states of sulfur tend to have stronger S-O bonds.
Let's go through each species:
1. SO2 (sulfur dioxide): In SO2, sulfur has an oxidation state of +4. The S-O bond strength is relatively weaker compared to species with higher oxidation states of sulfur.
2. SO32- (sulfite ion): In SO32-, sulfur has an oxidation state of +4. Compared to SO2, the presence of the negative charge on the ion makes the S-O bond slightly stronger.
3. SO3 (sulfur trioxide): In SO3, sulfur has an oxidation state of +6. The increase in oxidation state results in stronger S-O bonds compared to SO2 and SO32-.
4. SO (sulfur monoxide): In SO, sulfur has an oxidation state of +2. This corresponds to the lowest oxidation state of sulfur among the given species, resulting in weaker S-O bonds compared to the others.
Therefore, the correct order of decreasing S-O bond strength is: SO3 > SO32- > SO2 > SO.
So, your initial answer is incorrect. The correct order is: SO3, SO32-, SO2, SO.