A ball thrown up is caught by thrower 6 sec after start. The height to which the ball has risen is (g=10 m/s2)
so, it took 3 seconds to go up, and 3 to come down. So, with initial velocity v,
v-10*3 = 0
v = 30
h = 30t-5t^2
Now plug in t=3
To find the height to which the ball has risen, we can use the equation for the displacement of an object in freefall:
h = ut + (1/2)gt^2
where:
h = height
u = initial velocity (in this case, the velocity at which the ball was thrown up)
g = acceleration due to gravity (given as 10 m/s^2)
t = time
In this case, the ball is thrown up, so its initial velocity is positive. When the ball reaches its maximum height, its velocity will be zero.
Since the ball is caught by the thrower after 6 seconds, we can determine the time it takes for the ball to reach its maximum height by dividing the total time (6 seconds) by 2 (as the ball spends an equal amount of time going up and coming down):
t_max = 6 / 2 = 3 seconds
Now, let's calculate the height using the equation for displacement:
h = ut + (1/2)gt^2
Since the initial velocity (u) is the velocity at which the ball was thrown up, it would be positive. However, we don't have this information. Therefore, we cannot determine the exact height without knowing the initial velocity.