posted by Zachary
Two workers are sliding 450 kg crate across the floor. One worker pushes forward on the crate with a force of 380 N while the other pulls in the same direction with a force of 380 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor?
normal force = 450*9.81 = 4414. N
friction force = 4415 mu
380 + 380 = 4415 mu