Determine the molar concentration of sodium oxide if 3.91g of solid was added to 525mL of solution.
I am not typing my entire work in but I calculated these values:
V=525 ml= 0.525L
N= 0.0603084866
Would it be 0.120 mol/L
well I guess you are adding it to pure water
3.91g * (1000mL/L)/525 mL = 7.45 grams/liter
but we want mols per liter
Na2O is 62 g/mol because 2 * 23 + 16
7.45 g/L /62 g/mol = .12 mol/L
So my answer is right?
To determine the molar concentration of sodium oxide, you need to use the formula:
Molar Concentration (M) = moles of solute / volume of solution in liters
First, you need to calculate the moles of sodium oxide. To do this, you can use the molar mass of sodium oxide, which is the sum of the atomic masses of sodium (Na) and oxygen (O).
Molar mass of Na = 22.99 g/mol
Molar mass of O = 16.00 g/mol
So the molar mass of Na2O (sodium oxide) is:
2 x (22.99 g/mol) + 16.00 g/mol = 61.98 g/mol
Now, we can calculate the moles of sodium oxide by dividing the given mass (3.91 g) by the molar mass:
moles = mass / molar mass = 3.91 g / 61.98 g/mol ≈ 0.0629 mol
Next, you need to convert the volume of the solution from milliliters (mL) to liters (L). In this case, the volume is given as 525 mL, so divide it by 1000 to get the volume in liters:
volume = 525 mL / 1000 = 0.525 L
Finally, substitute the values into the formula for molar concentration:
Molar Concentration = 0.0629 mol / 0.525 L ≈ 0.120 M
So, the molar concentration of sodium oxide in this solution is approximately 0.120 M.