Algebra 1
posted by help plz .
Glenda, Hilda, and Inez have $35,000 invested in a business. Glenda's investment is onehalf Hilda's and three times Inez's investment. How much does each person have invested?

Glenda's  x
Hilda's  2x
INez's  (1/3)x
x + 2x + x/3 = 35000
multiply each term by 3
3x + 6x + x = 105000
solve for x, etc 
G + H + I = 35000
G = 1/2 H ... H = 2 G
G = 3 I ... I = G / 3
substituting ... G + 2G + G/3 = 35000
... 3G + 6G + G = 105000 ... G = 10500
substitute back to find H and I
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