A truck travels up a hill with a 5.7◦
incline.
The truck has a constant speed of 22 m/s.
What is the horizontal component of the
truck’s velocity?
Answer in units of m/s.
NEED HELP ASAP! ASSIGNMENT DUE IN 15 MIN
22 cos 5.7
To find the horizontal component of the truck's velocity, we need to use trigonometry. Let's break down the problem into two components: the horizontal component (Vx) and the vertical component (Vy).
Given:
Incline angle (θ) = 5.7°
Constant speed of the truck (V) = 22 m/s
We know that the horizontal component of a vector can be calculated using the formula:
Vx = V * cos(θ)
Now, let's substitute the values into the formula and solve for Vx:
Vx = 22 m/s * cos(5.7°)
To calculate this, you can use a calculator or mathematical software. By plugging in the values and evaluating the expression, you'll get the answer for the horizontal component of the truck's velocity.