posted by Ashley
13.5ml of hydrogen iodide are produced by the reaction of 8.1ml of hydrogen and 9.3ml of iodine vapor at444°c. Calculate the Kc at this temperature
mols H2, use PV = nRT and calculate n.
mols I2 do the same and find n.
Then initial (H2) = n/L and initial (I2) = n/L
Do you have a pressure? or some other way to calculate n?
....H2 + I2 ==> 2HI