# algebra

posted by Brooke

Tickets to a sporting event cost \$6 for children and \$8 for adults. The total revenue from the tickets sold was \$2340. There were 320 total tickets sold.

How many children’s tickets were sold?

1. Scott

c + a = 320

6c + 8a = 2340

8c + 8a = 8(320)

2c = 8(320) - 2340

2. Laurie

110 children's tickets were sold and 210 adult tickets were sold. Using the first 2 equations set up by Scott & ignoring the last 2 steps, I used substitution to solve for c "the number of children's tickets sold.

6c+8(320-c)=320

6c+2560-8c=320

-2c+2560=320

-2c=-220

c=110

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