9.3mL of ammonia base cleaner requires 12mL of 1M HCL to reach end point. A) what is molarity of ammonia and b) what is percentage of ammonia
NH3 + HCl ==> NH4Cl
mols HCl = M x L = ?
mols NH3 = the same. Look at the coefficients in the balanced equation.
M NH3 = mols NH3/L NH3 = ?
For percentage is that w/w, w/v, what?
I will assume w/v (weight/volume).
mols NH3 from above x molar mass NH3 = grams NH3.
Then (g NH3/9.3 mL)*100 = % NH3 w/v