chemistry

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A compound is found to have 61% carbon, 6.6% hydrogen, and 32.6% oxygen. What is the empirical formula of this compound?

I got C25H32H10 but the subscripts seem absurdly large.

  • chemistry -

    I think you are right about that. If you had shown your work I would have found your error.

  • chemistry -

    61/12.01 = 5.079/2.0375 = 2.5

    6.6/1.008 = 6.5476/2.0375= 3.21

    32.6/16 = 2.0375/2.0375= 1

    I know to get the empirical formula, i Have to make these all whole numbers so I multiplied by 10 to get C25H32O10.

  • chemistry -

    The error is you used H2 and not H.
    6.6/1 = 6.6 so you have
    C = 5
    H = 6.6
    O = 2
    Now multiply everything by 3 to get
    C 15
    H 19.8
    O = 6
    Then round to whole numbers.
    I didn't divide by the smallest number, as I'm supposed to do, I just skipped that step since I had two whole numbers already so by multiply everything by 3 I got all whole numbers. If you do it the other way, you get
    C 5/2 = 2.5
    H 6.6/2 - 3.3
    O 2/2 = 1
    Multiply everything by 6 to get
    C 15
    H 19.8
    O 6
    Hope this helps.

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