A statistics class is made up of 60% women and has 21 women in it. What is the total number of students in the class?
Suppose you flip a fair coin (i.e., a coin that lands Heads with probability 1/2 and Tails with probability 1/2) 100 times. Which is more likely:
Is there a formula for this? Please I need help
12.6
To find the total number of students in the class, we can use the concept of proportion. We know that the percentage of women in the class is 60%, and we also know that there are 21 women in the class.
Let's use the variable "x" to represent the total number of students in the class.
Since 60% of the class are women, we can express this as a proportion:
(60/100) * x = 21
Now, let's solve for "x":
(60/100) * x = 21
To clear the fraction, we multiply both sides of the equation by 100:
60x = 21 * 100
Now, divide both sides of the equation by 60 to solve for "x":
x = (21 * 100) / 60
x = 2100 / 60
x ≈ 35
Therefore, the total number of students in the class is approximately 35.