Algebra
posted by Keonn'a .
Find an equation of a line perpendicular to the given line and contains the given point. Write the equation in slopeintercept form.
a. line 3x+y=5, point (1,2)
b. line y=3x+1, point (6,1)

do like the other one, but use the perpendicular slope.
3x+y=5 has slope 3
so, the perpendicular line has slope 1/3
The new line is thus
y2 = 1/3 (x+1)
now rearrange to slopeintercept form
do the other one in like wise.
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