Algebra

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Find an equation of a line parallel to the given line and contains the given point. Write the equation in slope-intercept form.

a. line 2x+3y=2 , point (0,0)

b. line y+4=0, Point (-5,3)

• Algebra -

2x+3y=2 has slope -2/3
So, using the point-slope form, the new line is

y-0 = -2/3 (x-0)
y = -2/3 x

y+4=0
y = -4 has slope 0
the horizontal line through (-5,3) is
y=3

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