A rectangular room is 1.2 times as long as it is wide, and its perimeter is
25 meters. Find the dimension of the room rounded to the nearest tenth.
The length is:
The Width is:
L = 1.2W
2L + 2W = 25
Substitute 1.2W for L in the second equation and solve for W. Insert that value into the first equation to solve for L. Check by putting both values into the second equation.
2
8
To find the dimensions of the room, we can set up a system of equations based on the given information.
Let's assume the width of the room is "x" meters.
Since the room is 1.2 times as long as it is wide, the length of the room would be 1.2x meters.
The perimeter of a rectangle is given by the formula: 2(length + width).
Therefore, the equation for the perimeter of this room would be:
2(1.2x + x) = 25
Simplifying the equation, we have:
2(2.2x) = 25
4.4x = 25
x = 25/4.4
x ≈ 5.7
So, the width of the room would be approximately 5.7 meters.
Now, let's find the length of the room using the width we just found.
Length = 1.2 * Width
Length ≈ 1.2 * 5.7
Length ≈ 6.8
Therefore, the length of the room would be approximately 6.8 meters.
To summarize:
The length of the room is approximately 6.8 meters.
The width of the room is approximately 5.7 meters.