math
posted by Anonymous .
A person invested 1100 rs in a company at compound interest compounded semiannually.he received rs 1331 after one year.rate% is?

let the semiannual rate be i
amount after 1 year = 1100(1 + i)^2
interest = 1100(1 + i)^2  1100 = 1331
1100(1 + i)^2 = 2431
(1+i)^2 = 2.21
1+i = √2.21 = appr 1.4866
i = .4866
WOW, annual rate is .4866(2) = .9732 or 97% ?????
check: 1100(1.4866..)^2 = 2430.98
interest = 1330.98 or 1331 rs
Seems unreasonable high to me, do you have a typo ?? 
answer rate 20%

poorly worded question,
so the amount is 1331 rs, then
1100(1+i)^2 = 1331
(1+i)^2 = 1.21
1+i = √1.21 = 1.1
i = .1 or 10%
so the annual rate is 20%
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