Quadratic equations
posted by Anonymous .
A ball is thrown vertically upwards From the top of a building of height 29.4 m and with an initial velocity 24.5 m/sec. If the height H of the ball from the ground level is given by H = 29.4 + 24.5t  4.9tÂ², then find the time taken by the ball to reach the ground

4.9 t^2 24.5 t 29.4 = 0
t^2  5 t  6 = 0
(t6)(t+1) = 0
t = 6 seconds (the 1 second is before release :)