Pre-Calculus 12

posted by Ryan

how to solve 3^(x-2) = 5^x

  1. Steve

    well, you need to get the x stuff isolated, so get rid of those exponents:

    (x-2) log3 = x log5
    x(log3-log5) = 2log3
    x = 2log3/(log3-log5) = log9/log(3/5) = log3/59

  2. Ryan


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