In the rhombus m<1=160. What are m<2 and m<3? The diagram is not drawn to scale.
To find m<2 and m<3 in the given rhombus, we need to apply the properties of rhombuses.
In a rhombus, opposite angles are congruent. So, if m<1 is 160 degrees, then m<3, opposite to m<1, will also be 160 degrees.
To find m<2, we need to recall that the sum of the angles in any quadrilateral is 360 degrees.
In a rhombus, the opposite angles are congruent, which means the sum of m<1 and m<3 will be equal to the sum of m<2 and m<4, where m<4 is the angle opposite to m<2.
So, m<1 + m<3 = m<2 + m<4
Since m<1 and m<3 are both 160 degrees, we can substitute their values into the equation:
160 + 160 = m<2 + m<4
Simplifying the equation gives:
320 = m<2 + m<4
However, since the diagram is not drawn to scale and no further information is provided, we cannot determine the specific values of m<2 and m<4.
To find the measures of angles m<2 and m<3 in a rhombus, we can use the properties of a rhombus.
1. In a rhombus, opposite angles are equal. Therefore, m<1=m<3. So, since m<1=160, we can also conclude that m<3=160.
2. The sum of the measures of all angles in a rhombus is always 360 degrees. Since we know that m<1=160 and m<3=160, we can find m<2 using the formula:
360 - (m<1 + m<3) = m<2
360 - (160 + 160) = m<2
360 - 320 = m<2
m<2 = 40
So, the measures of angles m<2 and m<3 are 40 degrees each.
adjacent angles of a rhombus are supplementary
... they add to 180º
opposite angles are congruent