Physics 11

posted by Kayla

Devon speeds past Tamara in his space shuttle. In Tamara's frame of reference, the shuttle moves with a speed of 0.88c. Devon's radio is blaring out music with a beat that occurs every 0.50 seconds. How often does Tamara hear the beats?

I'm getting 0.24 s but it's saying that's wrong...

0.50=t./(the root of: 1-(0.88c^2/c^2))

0.50=t./0.474974

t.=0.2375

1. Scott

one stays on Earth, the other goes on a high speed (close to c) trip

the one on Earth grows old, but when the traveler returns, he is still young

time passes slower in the high speed reference frame

so the beats will be wider spaced for Tamara

2. Scott

moving time = fixed time * dilation factor

0.50 = t * 0.474974

not sure why you had division, not multiplication

3. Kayla

You're right that does make sense, I got confused & mixed up t & t. if I switch them I get 1.1s.

Thank you :) I appreciate your help

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