Sudha is twice as old as Garima.10 years ago Sudha was three times as old as Garima.Find Sudha's present.
Let garima age be x year
And shudha age be 2x
And 10 year ago,garima age be (x-10)
10 year ago,shudha age be (2x-10)
Then a/q,
(X-10)=3(2x-10)
X-10=6x-30
X-6x=-30+10
-5x=-20
x=-20/-5
x=4
Hence,the garima age be 4 years
And the shudha age be 2x=2×4=8 years.
S = 2G
S-10 = 3(G-10)
Substitute 2G for S in the second equation and solve for G. Insert that value into the first equation to solve for S. Check by putting both values into the second equation.
To find Sudha's present age, we can follow these steps:
Step 1: Assign variables to Sudha and Garima's present ages.
Let's say Sudha's present age is S, and Garima's present age is G.
Step 2: Translate the given information into equations.
From the given information, we can write two equations:
Equation 1: Sudha is twice as old as Garima.
S = 2G
Equation 2: 10 years ago Sudha was three times as old as Garima.
(S - 10) = 3(G - 10)
Step 3: Solve the system of equations.
Substitute the value of S from Equation 1 into Equation 2:
(2G - 10) = 3(G - 10)
2G - 10 = 3G - 30
2G - 3G = -30 + 10
-G = -20
G = 20
Now substitute the value of G into Equation 1 to find Sudha's age:
S = 2(20)
S = 40
Therefore, Sudha's present age is 40 years.