Pre-Calculus 12

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how to graph y= (x^2-3x-10)/(x-2)

  • Pre-Calculus 12 -

    (x-5)(x+2)/(x-2)

    well we know it is 0 at x = 5 and at x = -2
    and we know it explodes at x = 2

    we know it goes to y = x as x gets +big

    we know it goes to y = -x as x gets -big

    now between those zeros at -2 and+5
    lies x = 0 when y is 10/2 = 5

    so that is a start :)

  • Pre-Calculus 12 -

    I don't understand what you mean "it is 0 at x=5 and at x=-2"?

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