Chemistry

posted by .

A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing point depression of the solvent if the freezing point constant is -1.86 °C/m?

• Chemistry -

delta T = Kf*m
Kf = 1.86
m = mols/kg solvent and mols = grams/molar mass. Substitute and solve for m.
Then substitute into dT = KfM and solve for dT. Post your work if you get stuck.

Similar Questions

1. Chemistry

calculate the freezing point of a solution containing 12.2 grams of benzoic acid, dissolved in 250 grams of nitrobenzene. the freezing point of nitrobenzene is 5.7 celsius and its freezing point depression constant is 7.0 celsius/m. …
2. Chemistry

A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m?
3. chemistry

A solution is made by dissolving 21.5 grams of glucose (C6H12O6) in 255 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m?
4. chemistry

A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m?
5. chemistry

A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m?
6. chemistry

A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m?
7. chemistry

1. Find the molality of the solution prepared by dissolving 0.238g toluene, C7H8, in 15.8g cyclohexane 2. A pure sample of the solvent phenol has a freezing point of 40.85 degrees C. A 0.414 molal solution of isopropyl alcohol was …
8. Chemistry

The equation for lowering the freezing point of a solvent is given in your manual. Given that the freezing point for the pure solvent is 79.4 °C , the molality is 0.1 m , and the freezing point depression constant is 6.9 °C/m , determine …
9. chemistry

A solution. Of glucose was prepared by dissolving certain amount in 100 grams of water ,the depression in freezing point is. 0.041kelvin if depression of water is 1.86 kelvin*kg/mol.calculate the weight of glucose dissolved .
10. Chemistry - Colligative Properties

The freezing-point depression for a given aqueous solution is 0.32 K. The freezing-point depression constant for water is 1.86 K/m. Calculate the molality of solutes in the solution. The equation for freezing point depression is ΔTf …

More Similar Questions