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Find the vertex focus directrix and axis of symmetry of each parabola y²–8x–6y–3=0

  • Math -

    looks like a horizontal parabola, let's complete the square
    y^2 - 6y + 9 = 8x+3 + 9
    (y - 3)^2 = 8x + 12
    = 8(x + 3/2)

    from that version you should be able to pick out the vertex as (-3/2 , 3)

    recall that in y^2 = 4px the focus is (p,0) and the directrix is y = -p

    So from you equation, 4p = 8, then p = 2
    the focus is(2-3/2, 3), or (-1/2 , 3)
    and the directrix is ........

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