posted by Shilpa saxena .
The electrolysis of 250ml of a brine solution was carried out for a period of 20mins with a current of 2A. The resulting solution was titrated with 0.62M HCL. How many ml of HCL would be required to achieve natural point
2NaCl + 2H2O ==> Cl2 + H2 + 2NaOH
coulombs = amperes x seconds = approx 2400
96,485 coulombs will form 40 g NaOH.
g NaOH produced = 40 x 2400/96,485 = 0.995. How many mols is that? 0.995/40 = approx 0.25
Then you know the titration is
NaOH + HCl ==> NaCl + H2O
Approx (you need to do the exact number) 0.25 mol NaOH will require approx 0.25 mol HCl.
M HCl = mols HCl/L HCl. You know mols and M, solve for L