posted by ekuase .
Two cars are travelling at adjacent highway lanes in the same direction . Car B is stopped by car A which travels at 15km/hr. Then 2 seconds later car B starts and accelerate at a constant rate of 3 meter per seconds square . Determine when and where car B will overtake car A
Determine the speed of car B at that time
time for car a is t+2
time for car b is t
distance car a
= (15000 m/3600 s)(t+2)
distance car b = (1/2)(3)t^2
so when does car a travel the same distance as car b?
(150/36)(t+2) = (3/2) t^2
solve quadratic, use the t that makes sense :)
speed of b = 3 t