Algebra

posted by Anonymous

An amplifier has a 50 watt output and a 5 watt input. What is the gain in decibels for this amplifier, rounded to the nearest decibel?

  1. hi

    Power gain (G) is just [Power Out] / [Power In] In your case, that is

    G = 50 watts / 5 watts = 10

    To express that in decibels:

    Gain in dB = 10 * log(G) = 10 * log(10) = 10 * 1 = 10 dB

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