A stone of mass 2.8kg is projected upward with a speed of 5m/s. calculate the maximum height reached. use g=10m/s square.
Vo = 5 m/s = Initial velocity.
V = 0 = Final velocity = Velocity at max. ht.
g = -10 m/s.
V^2 = Vo^2 + 2g*h. h = ?.
The answer is 22.3m for the maximum height.
0 = 5^2 - 2*10*h,
20h = 25, h = 1.25 m.
A 2nd method:
V = Vo + g*t
0 = 5 -10t, t = 0.5 s.
h = Vo*t + 0.5g*t^2,
h = 5*0.5 - 5*0.5^2,
h = 2.5 - 1.25 = 1.25 m.
A 3rd Method:
KE = PE.
0.5M*Vo^2 = Mg*h
1.4*5^2 = 2.8*10*h
35 = 28h, h = 1.25 m.
Based on the information given, your answer is incorrect.
To calculate the maximum height reached by the stone, we can make use of the kinematic equation for vertical motion:
Final velocity squared (v^2) = Initial velocity squared (u^2) + 2 * acceleration (a) * displacement (s)
In this case, the final velocity (v) is 0 m/s because at the maximum height, the stone momentarily comes to rest before falling back down.
The initial velocity (u) is +5 m/s because the stone is projected upward.
The acceleration (a) is -10 m/s^2, taking the direction of gravity into account. Since the stone is moving upward against gravity, the acceleration is negative.
The displacement (s) is what we want to find - the maximum height reached by the stone.
Rearranging the equation, we have:
0 = (5^2) + 2 * (-10) * s
Simplifying further:
0 = 25 - 20s
Rearranging again:
20s = 25
Dividing both sides by 20:
s = 25 / 20
Therefore, the maximum height reached by the stone is 1.25 meters.