A professional baseball player pitchers a ball giving it a velocity of 45m/s towards the butter. The batted ball has a velocity of 30m/s towards the pitcher. Let the direction from the batter to the pitcher be the positive direction. If the change in velocity takes place over a period of 1.2s, what was the average acceleration of the baseball?
V1 = -45 m/s.
V2 = 30 m/s.
a = (V2-V1)/t = (30-(-45))/1.2 =
post.
Oops! Not anonymous.
To find the average acceleration of the baseball, we can use the equation:
average acceleration = (change in velocity) / (change in time)
From the given information, we know that the change in velocity is:
(change in velocity) = final velocity - initial velocity
The initial velocity of the baseball is 45m/s (pitched ball) towards the batter, and the final velocity is 30m/s (batted ball) towards the pitcher. Since we are taking the direction from the batter to the pitcher as the positive direction, we need to assign negative signs to the velocities:
initial velocity = -45m/s
final velocity = -30m/s
Substituting these values into the equation for change in velocity:
(change in velocity) = -30m/s - (-45m/s)
(change in velocity) = -30m/s + 45m/s
(change in velocity) = 15m/s
Now, we need to determine the change in time. The problem states that the change in velocity takes place over a period of 1.2s:
(change in time) = 1.2s
Finally, substituting the values into the equation for average acceleration:
average acceleration = (change in velocity) / (change in time)
average acceleration = 15m/s / 1.2s
average acceleration = 12.5 m/s²
Therefore, the average acceleration of the baseball is 12.5 m/s².