If 12.0 ml of a 0.050M sodium acetate is added to 22.0ml of water, what is the final concentration of the NaC2H3O2?
To find the final concentration of NaC2H3O2, we use the formula:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
In this case, the initial concentration (C1) is 0.050M, the initial volume (V1) is 12.0 ml, and the final volume (V2) is the sum of the initial volume and the volume of water added (12.0 ml + 22.0 ml = 34.0 ml).
Now, let's substitute the values into the formula:
(0.050M)(12.0 ml) = C2(34.0 ml)
Multiply 0.050M and 12.0 ml:
0.60 = C2(34.0 ml)
Next, divide both sides of the equation by 34.0 ml:
0.60 / 34.0 ml = C2
The final concentration of NaC2H3O2 is approximately 0.0176 M.