calculus
posted by Sam .
The base of a certain solid is the triangle with vertices at (−6,3), (3,3), and the origin. Crosssections perpendicular to the yaxis are squares. Then the volume of the solid?

Think of the solid as a stack of thin squares. At a distance y from the origin, the square has side 3y. So, add them all up and the volume is
∫[0,3] (3y)^2 dy
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