Algebra I
posted by Cale
Scott wants to make 6 gal of a 50% sugar solution by mixing together a 60% sugar solution and pure water. How much of each solution must he use?
mixture 1 @ 60% = x gallons
pure water = 100%  x (??? that's my question...is that correct? or is it 0?)
mixture @ 50% = 6 gallons
60x + 100(6x)= 50 * 6
60x + 600100x = 300
600  40x = 300
40x = 300
x = 7.5

Reiny
I would do it this way:
Amount of pure water needed  x gal
Amount of the 60% stuff  6x
.6(6x) + 0x= .5(6)
3.6  .6x = 3
.6x = .6
x = 1
so use 5 gal of the 60% plus 1 gal of pure water
your answer of 7.5 gal should have made no sense to you. You want to end up with only 6 gal, so how could you add 7.5 ???? 
Cale
Thank you. My answer of 7.5 didn't make sense. i was obviously overthinking...thinking pure would = 100%.
Again, thanks for your help.
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