Algebra I

posted by Cale

Scott wants to make 6 gal of a 50% sugar solution by mixing together a 60% sugar solution and pure water. How much of each solution must he use?

mixture 1 @ 60% = x gallons
pure water = 100% - x (??? that's my question...is that correct? or is it 0?)
mixture @ 50% = 6 gallons

60x + 100(6-x)= 50 * 6
60x + 600-100x = 300
600 - 40x = 300
-40x = -300
x = 7.5

  1. Reiny

    I would do it this way:
    Amount of pure water needed --- x gal
    Amount of the 60% stuff ------ 6-x

    .6(6-x) + 0x= .5(6)
    3.6 - .6x = 3
    -.6x = -.6
    x = 1

    so use 5 gal of the 60% plus 1 gal of pure water

    your answer of 7.5 gal should have made no sense to you. You want to end up with only 6 gal, so how could you add 7.5 ????

  2. Cale

    Thank you. My answer of 7.5 didn't make sense. i was obviously overthinking...thinking pure would = 100%.
    Again, thanks for your help.

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