Find the sum of the first eight terms of a linear sequence whose first term is 6 and whose last term is 46

Sn = n/2 (A1+An)

= 8/2 (6+46)

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IS IT 208

S/n =n/2[A+D]

A=6
D=46
8/2 [6+46]
4[52]
208

To find the sum of the first eight terms of a linear sequence, you can use the formula for the sum of an arithmetic series:

Sn = n/2 * (a + l)

Where:
Sn is the sum of the first n terms
n is the number of terms
a is the first term
l is the last term

In this case, the first term (a) is 6 and the last term (l) is 46. We need to find the sum of the first 8 terms (n = 8).

Using the formula, we can calculate the sum:

S8 = 8/2 * (6 + 46)
= 4 * 52
= 208

Therefore, the sum of the first eight terms of the linear sequence is 208.

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