A sells to B at a gain of 20%,B sells to C at a price A paid.what does B lose as a percentage?
Plz show step with neat algebras
i tried working it out i become angry with the question
u make me confuse the more
plz explain wel
they got 2/3 here in my text book
2/3=0.666
and u got 16.666
how
To solve this problem, let's break it down into steps and use algebra to find the answer. Let's assume the cost price of A is $100.
Step 1: A sells to B at a gain of 20%
Since A sells to B at a gain of 20%, A sells to B at a price that is 120% of the cost price of A.
Price at which A sells to B = (Cost price of A) * (120/100) = 100 * (120/100) = $120.
Step 2: B sells to C at a price A paid.
B sells to C at the same price that A paid, which is $120.
Step 3: Finding the loss percentage for B
The loss percentage for B can be calculated by finding the difference between the cost price for B and the selling price to C, and then expressing it as a percentage of the cost price for B.
Let's say the cost price for B is "x".
Selling price to C = x (since B sells to C at the price A paid, which is $120).
Loss = Cost price for B - Selling price to C
Loss = x - x = 0
Loss percentage = (Loss / Cost price for B) * 100
= (0 / x) * 100
= 0%
Therefore, B does not lose any percentage since the selling price to C is equal to the cost price for B.
Note: It's important to carefully read and understand the question and avoid becoming frustrated. Breaking down the problem into steps and using algebra can help simplify complex problems.
B = 1.20A
C = A = B/1.20 = (5/6)B
so, that is ...
come on.
B paid 20% of A's cost: 1.20A
C paid what A did: B/1.20 = 08.3333B
So, B lost 16.666 %
maybe my math looks as funny to you as your texting does to me...