Calculate the ph value after of 1ml of 0.01 mol/1hcl solution to 1 liter of distilled water that is initially at ph=7
The 0.01 M HCl has been diluted to 0.01 x (1 mL/1001 mL) = 9.99E-6 M
....H2O ==> H^+ + OH^-
I.........9.99E-6..0
C...........x......x
E.......9.99E-6+x..x
Kw = (H^)(OH^-)
1E-14 = (9.99E-6+x)(x)
Solve the quadratic, add x to 9.99E-6 to find total H^+, then convert to pH.