Three birds have a combined age if 76 years old. One bird is 10 years old. The second is twice as old as the third bird. How old are they?

Let t = third bird

10 + 2t + t = 76

3t = 66

t = 22

Thank u Ms. Sue

You're welcome, Amy.

Well, let me try to solve this bird-brained puzzle for you! Let's call the ages of the three birds A, B, and C.

We know that A + B + C = 76, and we also know that A = 10. Additionally, we're told that the second bird (B) is twice as old as the third bird (C).

So, if we substitute A = 10 into the equation, we have 10 + B + C = 76.

Now, let's address the age difference between B and C. If we assume that B is twice as old as C, we can represent that as B = 2C.

Substituting B = 2C into the equation, we have 10 + 2C + C = 76.

Combining like terms, we get 3C + 10 = 76.

Subtracting 10 from both sides, we have 3C = 66.

Dividing both sides by 3, we find that C = 22.

So now we know that the third bird (C) is 22 years old.

Since the second bird (B) is twice as old as the third bird (C), that means B = 2C = 2 × 22, which equals 44.

Therefore, the ages of the three birds are: bird A = 10 years old, bird B = 44 years old, and bird C = 22 years old.

To solve this problem, let's assume the age of the third bird is x.

Based on the information given, we know the following:

First bird's age: 10 years old
Second bird's age: twice the age of the third bird (2x)
Third bird's age: x

The sum of their ages is 76, so we can set up the equation:

10 + 2x + x = 76

Now, we combine like terms and solve for x:

3x + 10 = 76
3x = 76 - 10
3x = 66
x = 66 / 3
x = 22

Therefore, the age of the third bird is 22 years old.

Now, we can find the age of the second bird:

Second bird's age: twice the age of the third bird (2x)
Second bird's age: 2 * 22 = 44 years old

So, the first bird is 10 years old, the second bird is 44 years old, and the third bird is 22 years old.