I am a six-digit number between 600,000 and 700,000. The digit in the ten thousands place is 1 more than the digits in the thousands and hundreds place. The digit in the hundreds place is 3. The sum of the digits in the ones and tens place equals the digits in the hundred thousands place.
number between 600,000 and 700,000
6xx,xxx
The digit in the hundreds place is 3.
6xx,3xx
The digit in the ten thousands place is 1 more than the digits in the thousands and hundreds place.
643,3xx
The sum of the digits in the ones and tens place equals the digits in the hundred thousands place.
last two digits are among
06, 15, 24, 33, 42, 51, 60
If you wanted unique digits, then the 3rd condition is unclear.
vcfygi
To find the six-digit number, let's analyze the information provided:
1. The digit in the hundreds place is 3.
2. The digit in the ten thousands place is 1 more than the digits in the thousands and hundreds place.
3. The sum of the digits in the ones and tens place equals the digits in the hundred thousands place.
Based on this information, let's solve it step-by-step:
Step 1: The digit in the hundreds place is 3.
Since we know the digit in the hundreds place is 3, we can write the number as *3******, where * represents unknown digits.
Step 2: The digit in the ten thousands place is 1 more than the digits in the thousands and hundreds place.
Since the digit in the hundreds place is 3, the digit in the ten thousands place is 1 more than 3, which means it is 4. Now we can update the number as *34*****.
Step 3: The sum of the digits in the ones and tens place equals the digits in the hundred thousands place.
The only way the sum of the ones and tens place will be equal to the digit in the hundreds of thousands place is if both the ones and tens place are 0.
So, the final six-digit number that satisfies all the given conditions is 403000.
To find the six-digit number, let's break down the given information step by step.
Step 1: The digit in the hundreds place is 3.
This means the number must have a 3 in the hundreds place.
Step 2: The digit in the ten thousands place is 1 more than the digits in the thousands and hundreds place.
Since the digit in the hundreds place is 3, the digit in the ten thousands place must be 4 (3 + 1).
Step 3: The sum of the digits in the ones and tens place equals the digits in the hundred thousands place.
The digit in the hundred thousands place can be found by subtracting the sum of the digits in the ones and tens place from the digit in the ten thousands place. The digit in the ten thousands place is 4.
Let's calculate the sum of the digits in the ones and tens place:
From the given conditions, we know that the digit in the tens place is equal to the digit in the ones place.
So, let's assume the digit in the ones place is x. Then the digit in the tens place is also x.
The sum of the digits in the ones and tens place is x + x = 2x.
To find the digit in the hundred thousands place, subtract the sum of the digits in the ones and tens place (2x) from the digit in the ten thousands place (4):
4 - 2x = x
Simplifying the equation, we get:
4 = 3x
Dividing both sides of the equation by 3, we find:
x = 4/3
However, since we are looking for a digit, x must be an integer. Therefore, there is no valid solution that satisfies all the conditions.
Hence, there is no six-digit number that meets all the given conditions.