The number of boys👦 in a school🏢 is 334 more than the number of girls👧. If the total strength👦👧 of the school🏢 is 572,find the number of girls👧 in the school.
Let the no. Of girl be. X
no .of girl =x
no.of boy = x+334
Total no .of strength= 572
A/Q
X+(x+334)=572
2x+334=572
2x=572-334
2x=238
X=238/2
X=119
Very good ans
Let boys=x & girls=y x-y=334 i.e eqn 1 x+y=572 i.e eqn 2 put x=572-y from eqn 2 in eqn 1 ie (572-y)-y=334 -2y=-572+334 -2y=-238 hence y=119 put y=119 into eqn 1 x-119=334 x=453 Hence boys=453 girls=119
B 453,g 119
Helped me alot
To solve this problem, we can set up an equation based on the given information.
Let's assume the number of girls in the school is represented by 'G', and the number of boys is represented by 'B'.
The problem states that the number of boys is 334 more than the number of girls. This can be expressed as:
B = G + 334
The problem also states that the total strength of the school is 572. This can be expressed as:
B + G = 572
Now, we can substitute the value of B from the first equation into the second equation:
(G + 334) + G = 572
Simplifying the equation:
2G + 334 = 572
Next, subtract 334 from both sides:
2G = 572 - 334
2G = 238
Finally, divide both sides by 2 to solve for G:
G = 238 / 2
G = 119
Therefore, the number of girls in the school is 119.
b = g + 334
b + g = 572
substituting
... g + 334 + g = 572