physics question
posted by himel
In a projectile motion, the horizontal range and the maximum height attained by the projectile are equal .
A) what is the launch angle?
B) If everything else slays the same , how should the launch angle, ¦È0, of a projectile be changed for the range of the projectile to be halve?

himel
be halved??

Steve
recall that
range = v^2/g sin(2θ)
height = v^2/g sin^2(θ)
so, solve for θ
an excellent discussion of trajectories for all your problems can be found at
https://en.wikipedia.org/wiki/Trajectory 
himel
thanks a lot sir@Steve
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