physics question

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In a projectile motion, the horizontal range and the maximum height attained by the projectile are equal .
A) what is the launch angle?
B) If everything else slays the same , how should the launch angle, ¦È0, of a projectile be changed for the range of the projectile to be halve?

  • physics question -

    be halved??

  • physics question -

    recall that

    range = v^2/g sin(2θ)
    height = v^2/g sin^2(θ)

    so, solve for θ

    an excellent discussion of trajectories for all your problems can be found at

    https://en.wikipedia.org/wiki/Trajectory

  • physics question -

    thanks a lot sir@Steve

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