Ammonia decomposes upon heating to produce nitrogen and hydrogen elemental products. Write a balanced equation and then use stoichiometry problem solving to determin the mass of nitrogen product that can form if exactly 25.50 grams of ammonia(NH3) is fully decomposed.
well, you can start off with
2NH3 = N2 + 3H2
now start by changing moles
To write a balanced equation for the decomposition of ammonia, we need to remember that ammonia contains one nitrogen atom (N) and three hydrogen atoms (H).
The balanced equation for the reaction is:
2 NH₃(g) → N₂(g) + 3 H₂(g)
Now, let's solve the stoichiometry problem to determine the mass of nitrogen formed when 25.50 grams of ammonia is fully decomposed.
Step 1: Find the molar mass of NH₃:
The molar mass of NH₃ is calculated by adding up the molar masses of its constituent elements.
Molar mass of N = 14.01 g/mol
Molar mass of H = 1.01 g/mol
Therefore, molar mass of NH₃ = (14.01 g/mol) + 3(1.01 g/mol) = 17.04 g/mol
Step 2: Determine the moles of NH₃:
Moles = Mass / Molar mass
Moles of NH₃ = 25.50 g / 17.04 g/mol ≈ 1.497 mol (rounded to three decimal places)
Step 3: Using the balanced equation, apply stoichiometry to find the moles of nitrogen:
From the balanced equation, we see that 2 moles of NH₃ produce 1 mole of N₂.
Therefore, 1.497 mol of NH₃ will produce (1/2) × 1.497 mol of N₂ = 0.7485 mol of N₂
Step 4: Convert moles of nitrogen to grams:
Moles = Mass / Molar mass
Mass of N₂ = 0.7485 mol × 28.02 g/mol ≈ 20.95 g (rounded to two decimal places)
Therefore, when 25.50 grams of ammonia is fully decomposed, approximately 20.95 grams of nitrogen will be formed.