A major component of gasoline is octane C8H18. When octane is burned in air, it chemically reacts with oxygen gas O2 to produce carbon dioxide CO2 and water H2O.
What mass of octane is consumed by the reaction of 8.8g of oxygen gas?
Round your answer to 2 significant digits.
0 MOL
To determine the mass of octane consumed by the reaction of 8.8g of oxygen gas, we can use the balanced chemical equation for the combustion of octane. The balanced chemical equation is as follows:
2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O
From the balanced chemical equation, we can see that the stoichiometric ratio between octane (C8H18) and oxygen gas (O2) is 25:2. This means that for every 25 moles of O2, 2 moles of octane are consumed.
To find the mass of octane consumed, we can follow these steps:
Step 1: Convert the mass of oxygen gas (given) to moles.
Use the molar mass of oxygen (O2) to convert grams to moles. The molar mass of O2 is 32 g/mol (16 g/mol for each oxygen atom).
8.8 g O2 x (1 mol O2 / 32 g O2) = 0.275 mol O2
Step 2: Use the stoichiometric ratio to determine the moles of octane consumed.
Using the stoichiometric ratio from the balanced chemical equation, we can determine the moles of octane consumed.
0.275 mol O2 x (2 mol C8H18 / 25 mol O2) = 0.022 mol C8H18
Step 3: Convert moles of octane to grams.
To find the mass of octane consumed, we can use the molar mass of octane. The molar mass of octane (C8H18) is 114.23 g/mol.
0.022 mol C8H18 x (114.23 g C8H18 / 1 mol C8H18) = 2.51 g C8H18
Therefore, 8.8g of oxygen gas would consume 2.51g of octane.
To determine the mass of octane consumed by the reaction of 8.8g of oxygen gas (O2), we need to use the balanced chemical equation and the molar ratios.
The balanced chemical equation for the combustion of octane (C8H18) is:
C8H18 + 12.5O2 → 8CO2 + 9H2O
The molar ratio between octane and oxygen gas is 1:12.5. This means that for every 1 mole of octane, 12.5 moles of oxygen gas are required.
To find the mass of octane consumed, we need to convert the mass of oxygen gas to moles and then use the molar ratio to determine the moles of octane consumed.
1. Convert the mass of oxygen gas to moles:
Moles of O2 = Mass of O2 / Molar mass of O2
The molar mass of oxygen gas (O2) is 32.00 g/mol (16.00 g/mol * 2).
Moles of O2 = 8.8 g / 32.00 g/mol
Moles of O2 ≈ 0.275 mol
2. Use the molar ratio to determine the moles of octane consumed:
Moles of octane = Moles of O2 * (1 mole octane / 12.5 moles O2)
Moles of octane = 0.275 mol * (1 mol octane / 12.5 mol O2)
Moles of octane ≈ 0.022 mol
3. Calculate the mass of octane consumed:
Mass of octane = Moles of octane * Molar mass of octane
The molar mass of octane (C8H18) can be calculated as:
Molar mass of octane = (12.01 g/mol * 8) + (1.01 g/mol * 18)
Molar mass of octane ≈ 114.23 g/mol
Mass of octane = 0.022 mol * 114.23 g/mol
Mass of octane ≈ 2.51 g
Therefore, the mass of octane consumed by the reaction of 8.8g of oxygen gas is approximately 2.51 grams.