An object is placed 3cm in front of a convex mirror whose focal length is 12cm where is the image formed and what is it's nature
U=-3
F=12
1/v+1/u=1/f
1/v=1/3+1/12
1/v=2+1/6
1/v=1/3
V=3
M=-v/u
=-3/-3
=0
F=12
1/v+1/u=1/f
1/v=1/3+1/12
1/v=2+1/6
1/v=1/3
V=3
M=-v/u
=-3/-3
=0