Math

posted by Stacy

For a certain day,the depth of water,h, in metres in PEI, in hours is given by the formula:h(t) = 7.8sin (pi/6(t-3)), t E [0,24], assume t=0 represents midnight. Provide an algebraic solution to determine the time(s) of day, the water reaches the depth of 10.29 m( give your answer in hours and minutes)

  1. Steve

    Hmmm.

    7.8sin (pi/6(t-3)) = 10.29
    sin (pi/6(t-3)) = 1.319 <--- ??

    I suspect that you have left out a term in the definition of h(t). Fix it and then proceed with the solution.

  2. Stacy

    Sorry it's h(t)=7.8+3.5sin((pi/6(t-3))

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