The reaction between sulphuric acid and iron (III) hydroxide [Fe(OH)3] gives
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To determine the reaction between sulfuric acid (H2SO4) and iron (III) hydroxide (Fe(OH)3), we need to first consider the chemical formulas and respective charges of the involved compounds.
Sulfuric acid is a strong acid with the chemical formula H2SO4. It consists of two hydrogen ions (H+) and one sulfate ion (SO4^2-). Iron (III) hydroxide, represented by the formula Fe(OH)3, contains one iron (III) ion (Fe^3+) and three hydroxide ions (OH-).
Given this information, we can now balance the equation for the reaction by combining the individual ions:
H2SO4 + Fe(OH)3 -> ???
Since the hydroxide (OH-) ions from Fe(OH)3 and the hydrogen ions (H+) from H2SO4 can react to form water (H2O), it is reasonable to conclude that one molecule of Fe(OH)3 will react with two molecules of H2SO4. This would yield iron (III) sulfate (Fe2(SO4)3) and water (H2O):
2 H2SO4 + Fe(OH)3 -> Fe2(SO4)3 + 2 H2O
Thus, the reaction between sulfuric acid and iron (III) hydroxide results in the formation of iron (III) sulfate and water.