If The Rate of Diffusion Of Oxygen Is Taken As The Rate Of 1. What Will Be The Rate Of Diffusion Of Methane Whose Relative Molecular Mass Is 16
To determine the rate of diffusion of methane, we need to use Graham's law of diffusion. Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
The formula for Graham's law can be written as:
r1/r2 = sqrt(M2/M1)
Where:
r1 = Rate of diffusion of gas 1
r2 = Rate of diffusion of gas 2
M1 = Molar mass of gas 1
M2 = Molar mass of gas 2
In this case, we want to find the rate of diffusion of methane (CH4), whose relative molecular mass is 16.
Let's assume the rate of diffusion of oxygen (O2) is taken as 1. We can substitute the known values into Graham's law and solve for the rate of diffusion of methane.
r1/1 = sqrt(32/16) (as the relative molecular mass of oxygen is 32)
Simplifying the equation:
r1 = sqrt(32/16)
r1 = sqrt(2)
Therefore, the rate of diffusion of methane (CH4) will be approximately sqrt(2) units, assuming the rate of diffusion of oxygen is taken as 1.